Introduction to parseInt
- Building web server and its interactive functions
- Animations and graphics, adding special effects to web components
- Validating forms and exception errors
- Adding behavior and functionalities to web pages
The parseInt function takes a string as its first parameter, parses it, and then returns an integer or NaN. If the first argument is not NaN, the return value is the integer converted to a number in the chosen radix.
The parseInt() function parses a string argument and returns an integer with the radix or base given.
ParseInt parses the value of the input, whereas Number() transforms the type. The parseInt will only parse up to the first non-digit character, as you can see. Number, on the other hand, will attempt to convert the full string.
The parseInt() function takes the string, radix as an argument, and converts it to an integer. The radix option specifies which numeral system to use; for example, a radix of 16 (hexadecimal) indicates that the number in the string should be converted from hexadecimal to decimal. It returns NaN, or not a number if the text does not include a numeric value.
Syntax of parseInt
The parseInt() method is represented by the following syntax:
The string to be parsed is represented by the parameter string.
radix – This is an optional parameter. The number system to be utilized is represented by an integer between 2 and 36.
Return- The number is an integer. If the initial character cannot be translated to a number, it returns NaN.
The following parameters are accepted by this function, as mentioned above and described below:
This parameter’s value is a string that has been transformed into an integer.
radix: This argument is optional and represents the radix or base to be utilized.
The value returned: The function returns a number, and if the initial character cannot be translated to a number, it returns NaN. It actually returns a number that has been parsed until it comes across a character that isn’t a number in the chosen radix (base).
Example 1: The n contains 2018 since ‘@’ is not a Number and parsing terminates at that point, ignoring any additional characters.
Input: var n = parseInt(“2018@codedamn”);
Output: n = 2018
Input: var a = parseInt(“1000”);
Output: a = 1000(Number)
If you have any queries or feedback do let us know in the comment section.