# The Employee with the Longest Task

Easy
1
37.5% Acceptance

In this lab, you will work with a list of employees and the tasks they worked on. Your task is to find the employee who worked on the task with the longest time. If there is a tie between two or more employees, you will return the smallest id among them.

You are given a 2D integer array `logs` where `logs[i] = [idi, leaveTimei]` where:

• `idi` is the id of the employee that worked on the `ith` task, and
• `leaveTimei` is the time at which the employee finished the `ith` task. All the values `leaveTimei` are unique.

Note that the `ith` task starts the moment right after the `(i - 1)th` task ends, and the `0th` task starts at time `0`.

To complete the lab, you will need to implement the following function:

``````/**
* @param {number} n
* @param {number[][]} logs
* @return {number}
*/
var hardestWorker = function(n, logs) {

};``````

Example 1:

Input: n = 10, logs = [[0,3],[2,5],[0,9],[1,15]] Output: 1 Explanation: Task 0 started at 0 and ended at 3 with 3 units of times. Task 1 started at 3 and ended at 5 with 2 units of times. Task 2 started at 5 and ended at 9 with 4 units of times. Task 3 started at 9 and ended at 15 with 6 units of times. The task with the longest time is task 3 and the employee with id 1 is the one that worked on it, so we return 1.

Example 2:

Input: n = 26, logs = [[1,1],[3,7],[2,12],[7,17]] Output: 3 Explanation: Task 0 started at 0 and ended at 1 with 1 unit of times. Task 1 started at 1 and ended at 7 with 6 units of times. Task 2 started at 7 and ended at 12 with 5 units of times. Task 3 started at 12 and ended at 17 with 5 units of times. The tasks with the longest time is task 1. The employee that worked on it is 3, so we return 3.

Example 3:

Input: n = 2, logs = [[0,10],[1,20]] Output: 0 Explanation: Task 0 started at 0 and ended at 10 with 10 units of times. Task 1 started at 10 and ended at 20 with 10 units of times. The tasks with the longest time are tasks 0 and 1. The employees that worked on them are 0 and 1, so we return the smallest id 0.

Constraints:

• `2 <= n <= 500`
• `1 <= logs.length <= 500`
• `logs[i].length == 2`
• `0 <= idi <= n - 1`
• `1 <= leaveTimei <= 500`
• `idi != idi+1`
• `leaveTimei` are sorted in a strictly increasing order.

Challenges:

1. Write a function `hard-worker` that takes `n` and `logs` as input and returns the id of the employee that worked the task with the longest time.
2. Ensure that your solution handles cases where there is a tie between two or more employees correctly, returning the smallest id among them.
3. Ensure that your solution works correctly with the given inputs and constraints.